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The sum of the first three terms of an ap is 5 and the sum of their squares in 93. Find the AP pls tell the answer fast pls pls |
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Answer» -step EXPLANATION:LET THREE terms be a-d, a, a+dfrom the first condition,a-d+a+a+d = 53a = 5A = 5/3from SECOND condition,(a-d)^2+ (a)^2 + (a+d)^2 = 833a^2 + 2d^2 = 9325/3 + 2d^2 = 93 |
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