The sum of the measures of the angles of a triangle is equal to 108°.

1.	The sum of the measures of the angles of a triangle is equal to 108°.prove this statement using a diagram .
Answer» Answer: Step-by-step EXPLANATION: GIVEN : A triangle ABC. To prove : ∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction : Through A, draw a line l PARALLEL to BC. Proof : Since l∥BC. Therefore, ∠2=∠4 .......eq(i) And, ∠3=∠5......eq(ii) adding eq(i)and(ii) Therefore, ∠2+∠3=∠4+∠5 ∠1+∠2+∠3=∠1+∠4+∠5 [adding∠1bothSide] ∠1+∠2+∠3=180 o Thus, the SUM of three angles of a triangle is 180 o .

The sum of the measures of the angles of a triangle is equal to 108°.prove this statement using a diagram .

Answer»

Answer:

Step-by-step EXPLANATION:

A triangle ABC.

To prove :

∠A+∠B+∠C=180

⟹∠1+∠2+∠3=180

Construction :

Through A, draw a line l PARALLEL to BC.

Proof :

Since l∥BC. Therefore,

∠2=∠4 .......eq(i)

And, ∠3=∠5......eq(ii)

adding eq(i)and(ii)

Therefore, ∠2+∠3=∠4+∠5

∠1+∠2+∠3=∠1+∠4+∠5 [adding∠1bothSide]

∠1+∠2+∠3=180

Thus, the SUM of three angles of a triangle is 180