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The sum of the series `""^(3)C_(0)- ""^(4)C_(1) . (1)/(2) + ""^(5)C_(2)((1)/(2))^(2) - ""^(6)C_(3)((1)/(2))^(3) + ...` to `infty`, isA. 16B. 8C. `(16)/(81)`D. none of these |
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Answer» Correct Answer - c We have, `(1 + x)^(-n) = ""^(n-1)C_(0) - ""^(n)C_(1) x + ""^(n-1)C_(2) x + ""^(n+1)C_(2) x^(2) - ""^(n+2)C_(3) x^(3) + ...` On comparing the two series, we get n-1 = 3 a d` x = (1)/(2) rArr n=4 and x = (1)/(2)` Hence, sum of the given series = `(1 + (1)/(2))^(-4)` = (16)/(81)` . |
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