1.

The sum of the series , sin theta sec 3 theta sec 3^(2) theta + sin3^2theta3^(3) theta + .......... upto n terms , is

Answer»

`1/2[TAN3^(n) theta-tan3^(n-1)theta]`
`[tan3^(n) theta-tantheta)`
`1/2[tan3^(n) theta- TAN theta]`
`1/2 (tan3^(n) theta-1)`

ANSWER :C


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