| 1. |
The sum of the sides of a right angled triangle containing right angle is 17cm.If its area is 30 sq. cm. Find the length of the hypotenuse of the triangle. |
|
Answer» The area of a right triangle = 1/2 × b × h = 30 cm² Or, b × h = 30×2 Or, b×h = 60 BY Pythagoras Theorem, b²+h² = 13² Or, b²+h² = 169 By Formula (b+h)²=b²+h²+2bh Or, (b+h)²=169+2×60 Or, (b+h)²=169+120 Or, (b+h)²=289 Or, (b+h)²=17² Or, b+h=17 ---------- (1) By Formula (b-h)²=(b+h)²-4bh Or, (b-h)²=(17)²-4×60 Or, (b-h)²=289–240 Or, (b-h)²=49 Or, (b-h)²=7² Or, b-h=7 ---------- (2) Adding eq. (1) and (2) b+h+b-h = 17+7 Or, 2B = 24 Or, b = 24/2 Or, b = 12 cm Putting b = 12 in eq. (2) 12-h = 7 Or, h = 12 - 7 Or, h = 5 cm The difference between other two sides = b - h Or, The difference between other two sides = 12 - 5 Or, The difference between other two sides = 7 cm Therefore, the difference between other two sides = 7 cm |
|