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The sum of the squares of deviations for 10 observation taken from their mean 50 is 250. Find the co-effecient of variation. |
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Answer» Here, N = 10, \(\bar{x}\) = 50 And, \(\sum_{i=1}^{10} (x_i-50)^2=250\) ⇒ \(\frac{\sum_{i=1}^{10} (x_i-50)^2}{10}=25\) ⇒ σ2 = 25 ⇒ σ = 5 ∴ Co-effecient of variation, C.V = \(\frac{σ}{x}\times100\) = \(\frac{5}{50}\times100\) = \(\frac{500}{50}\) = 10 ∴ 10 is the co-effecient of variation. |
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