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The sum of the squares of two consecutive odd natural number is 202 Find the number with solving word problem​

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Answer:

Since they are consecutive odd INTEGERS, then we can just divide 202 by 2, SQUARE root it, then round to the nearest two odd integers. In this case, 202 / 2 = 101 ⇒ 1010.5 ≈ 10.04. The two nearest odd integers are 9 and 11. We can verify that this is the PAIR: 92 + 112 = 81 + 121 = 202.



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