The sum of three consecutive multiples of 3 is 108. find the multiples

1.	The sum of three consecutive multiples of 3 is 108. find the multiples
Answer» Answer: Step-by-step explanation: The NUMBERS are 33, 36 and 39. Explanantion: Let us SUPPOSE, the numbers are x, x +3 and x+6 Sum of them is: x + (x +3) + (x+6) = 108 => 3X + 9 = 108 => 3x = 99 => x = 33, which is divisible by 3 So the number are 33 (x), 36 (x+3) and 39 (x+6).

Answer»

Answer:

Step-by-step explanation:

The NUMBERS are 33, 36 and 39.

Explanantion:

Let us SUPPOSE, the numbers are x, x +3 and x+6

Sum of them is:

x + (x +3) + (x+6) = 108

=> 3X + 9 = 108

=> 3x = 99

=> x = 33, which is divisible by 3

So the number are 33 (x), 36 (x+3) and 39 (x+6).

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