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The sum of three consecutive multiples of 4 is 144. Find these multiples |
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Answer» A/Q4(X)+4(x+1)+4(x+2)4x+4x+4+4x+812x+12=14412x=144-1212x=132x=132/12×=11first MULTIPLE=x=11second multiple=(x+1)=11+1=12third multiple=(x+2)=11+2=13 |
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