The sum of three consecutive multiples of 4 is 36. find the multiples�

1.	The sum of three consecutive multiples of 4 is 36. find the multiples
Answer» ANSWER: Let the three CONSECUTIVE multiples of 11 are 11x, 11x+11 and 11x+22 Their sum is 363 11x+11x+11+11x+22=363 33x+33=363 33x=363−33 33x=330 x= 33 330 x=10 First MULTIPLE =11x=11×10=110 Second multiple =11x+11=110+11=121 Third multiple =11x+22=110+22=132

The sum of three consecutive multiples of 4 is 36. find the multiples

Answer»

Let the three CONSECUTIVE multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

330

x=10

First MULTIPLE =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132