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The sum of three consecutive multiples of 8 is 888.find the multiples |
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Answer» let THREE CONSECUTIVE multiple be 8x, 8(x+1),8(x+2)Step-by-step explanation:8x+8(x+1)+8(x+2)=8888(3x+3)=8883x+3=888/8 =1113x+3=1113x=111-33x=108x=108/3=368x=8multiply by 36=2888(x+1)=8(36+1)=2968(x+2)=8(36+2)=304so the consecutive multiple are 288,296,304 |
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