1.

The sum of three consecutive numbers is equal to 21. The equation to solve this problem is​

Answer»

Answer:

LET one number be x.

Then, the other number will be x+2.

The third number = x+2+2=x+4

It is GIVEN that their SUM is 21.

So, x+(x+2)+(x+4)=21

3x+6=21

3x=15

x=5

and x+2=7

x+4=9.



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