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The sum of three consecutive numbers is equal to 21. The equation to solve this problem is |
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Answer» Answer: LET one number be x. Then, the other number will be x+2. The third number = x+2+2=x+4 It is GIVEN that their SUM is 21. So, x+(x+2)+(x+4)=21 3x+6=21 3x=15 x=5 and x+2=7 x+4=9. |
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