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The sum of two consecutive multiples of 8 is 88. Find these multiples

Answer» 40 & 48Step-by-step explanation:LET X and x+8 be the two CONSECUTIVE multiples of 8.Given, x+x+8 =88 2x+8 =88 2x =80 x =40 x +8 =48Therefore, the two consecutive multiples of 8 are 40 and 48.


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