the sum of two numbers is 80. If the larger number exceeds four times

1.	the sum of two numbers is 80. If the larger number exceeds four times the smaller by 5, what is the smaller number?
Answer» ✬ Smaller Number = 15 ✬ Step-by-step explanation: Given: SUM of two numbers is 80. Larger numbers exceeds FOUR times the smaller by 5. To Find: What is the smaller number ? Solution: Let the larger number be x. Therefore, ➱ Smaller number = 80 – x A/q Larger number exceeds four times the smaller number by 5. $\implies{\rm }$ x = 4 $\times$ (80 – x) + 5 $\implies{\rm }$ x = 320 – 4x + 5 $\implies{\rm }$ x = 325 – 4x $\implies{\rm }$ x + 4x = 325 $\implies{\rm }$ 5x = 325 $\implies{\rm }$ x = 325/5 $\implies{\rm }$ x = 65 So, ➽ Larger number = x = 65 ➽ Smaller number = 80 – x => 80 – 65 => 15

the sum of two numbers is 80. If the larger number exceeds four times the smaller by 5, what is the smaller number?

Answer»

✬ Smaller Number = 15 ✬

Step-by-step explanation:

Given:

To Find:

Solution: Let the larger number be x. Therefore,

➱ Smaller number = 80 – x

A/q

$\implies{\rm }$ x = 4 $\times$ (80 – x) + 5

$\implies{\rm }$ x = 320 – 4x + 5

$\implies{\rm }$ x = 325 – 4x

$\implies{\rm }$ x + 4x = 325

$\implies{\rm }$ 5x = 325

$\implies{\rm }$ x = 325/5

$\implies{\rm }$ x = 65

So,

➽ Larger number = x = 65

➽ Smaller number = 80 – x

=> 80 – 65

=> 15