1.

the sums of parallel sides of a trapezium is 25 cm abd its area is 150cm² find its altiude do the solution quickly with the steps by steps​

Answer»

ANSWER:

  • Altitude (height) of Trapezium = 12 cm

GIVEN:

  • Sum of PARALLEL sides of a trapezium is 25 cm
  • Area of trapezium = 150 cm².

TO FIND:

  • Altitude of trapezium.

SOLUTION:

Formula

area \: of \: trapezium \: = \frac{1}{2} (sum \: of \: parallel \: side) \: \times height

Putting the VALUES we get;

\implies \: 150 = \frac{1}{2} \times 25 \times height \\ \\ \implies \: 150 = \frac{25}{2} \times height \\ \\ \implies \: 150 \times \frac{2}{25} = height \\ \\ \implies \: height \: = 12 \: cm

So Altitude (height) of Trapezium = 12 cm

NOTE:

some important formulas:

  • Area of parallelogram = BASE * Altitude
  • Area of rhombus = (Base * Altitude ) OR

= \frac{1}{2} \times (product \: of \: their \: diagonal)


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