The sun has a power of P=3.85xx10^(26) W and the only source of energy in it is the following reaction 4^(1)Hrarr.^(4)He+2e^(+)+2v_(0) The 'electron neutrinos (V_(e))' are nearly mass less and carry negligible energy. However, they are able to escape from the sun and have been detected on the earth. The Earth-sun distance is r=1.5xx10^(11)m and masses of a hydrogen ato, helium atom and a positron are 1.6740xx10^(-27)kg,6.6450xx10^(-27)kg and 0.0009xx10^(-27)kg respectively. (a) Calculate the flux density (i.e. number of neutrinos arriving at the Earth) in units of m^(-2)s^(-1). (b) While travelling from the Sun to the Earth, some of the electron neutrinos (V_(e)) are converted into other types of neutrinos -v_(0). the dectector on the Earth has (1)/(5) th efficiency for detecting v_(0) as compared to its efficiency to detect v_(0) Had there been no conversions of v_(e). we expect to detect N_(1) neutrinos in a year. However, due to conversion, we detect only N_(2) neutrinos (v_(0) and v_(e) combined) per year. what fraction (f) of v_(e) gets convertedinto v_(0). express your answer in terms of N_(1) and N_(2).