InterviewSolution
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InterviewSolution
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The sun rotates around itself once in`27` days. If it were to expand to twice its present diameter, what would be its new period of revolution ? |
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Answer» Here, `T_(1) = 27 days, R_(2) = 2R_(1), T_(2) = ?` Applying principle of conservation of angular momentum : `I_(2) omega_(2) = I_(1)omega_(1)` `((2)/(5)MR_(2)^(2)) (2pi)/(T_(2)) = ((2)/(5)MR_(1)^(2)) (2pi)/(T_(1))` `(R_(2)^(2))/(T_(2)) = (R_(1)^(2))/(T_(1))` or `T_(2) = (R_(2)^(2))/(R_(1)^(2)) xx T_(1) = (2)^(2) xx 27 = 108 days` |
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