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The surface charge density of a thin charged disc of radius R is sigma. The value of the electric field at the centre of the disc (sigma)/(2 epsilon_0) . With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc is |
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Answer» Solution :The electric field strength on the AXIS at a distance "x" from its centre of UNIFORM CHARGED circular disc is `E = (sigma)/(2 epsilon_0) (1-(x))/((x^2 + R^2)^(1//2))`. At centre , `E_(0) = (sigma)/(2 epsilon_0)` At distance `x = R`, `E = (sigma)/(2 epsilon_0) (0.37) = 0.37 E_0` |
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