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The surface of soap solution is `25xx10^-3Nm^-1`. The excess pressure inside a soap bubble of diameter 1 cm isA. 10 PaB. 20 PaC. 5 PaD. none of the above |
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Answer» Correct Answer - B Excess pressure `triangleP=(4T)/(r )` `=(4xx2xx25xx10^-3)/(1xx10^-2)` `=20(N)/(m^2)=20Pa` (as `r=(d)/(2)`) |
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