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The surface tension of a soap solution is 0.030N/m. What is the energy needed to increase the radius of the soap bubble from 4cm to 6cm. |
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Answer» Solution :`W = 2 xx T xx [4piR_2^2 - 4piR_1^2]` = `8piT [R_2^2 - R_1^2]` = `8 xx 3.14 xx 30 xx 10^-3 [36 -16] xx 10^-4` = `240 xx 3.14 xx 20 xx 10^-2` = `150 xx 10^-5 = 1.5 xx 10^-3 J` |
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