1.

The surface tension of ethenol at 30°C is 2.189 xx 10^(-2) Nm^(-1)and its density = 0.780 g/cc. To what height will this liquid rise in a capillary tube of radius 0.002 cm? What pressure is needed to push the miniscus level back with the surrounding liquid?

Answer»

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Solution :We have, `(2lambda)/(rdg)`
`d=0.78 g//cc = 0.78 kg//L = 0.78 xx 10^(3) kg//m^(3)`
`r=0.002 cm = 2.0 xx 10^(-4) m, g=9.8 m//s^(2)`
`therefore h=(2 xx 2.189 xx 10^(-2))/(2.0 xx 10^(-4) xx 0.78 xx 10^(3) xx 9.8) = 0.0286` m.
Further, the pressure (p) required to push the LIQUID back with the SURROUNDING liquid is given by:
`p=h.d.g`
`=0.0286 xx 0.78 xx 10^(3) xx 9.8`
`=218.6` PA (or `Nm^(-2)`)


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