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The surface tension of water = 72xx10^-3Jm^2. Find the work done in splitting a drop of water of 1mm into 64 small drops. |
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Answer» Solution :`4/3 pi R^3 = 64 xx 4/3 pi r^3` `therefore r^3 = (R^3)/(64)` `therefore r = R/4 = 1/4` mm initial surface energy `E_1 = 4piT (R^2)` FINAL surface energy `E_2 = 64 xx 4 piT (r^2)` `E_2 - E_1 = 4piT (64r^2 - R^2)` work done = `4piT (64r^2 - R^2) = 4piT(4 xx 10^-6 - 10^-6)` `12T xx 10^-6 = 2.7 xx 10^-6 J` |
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