1.

The surface which doesn.t reflect is given incidence light with 18 W//cm^(2) energy flux, than what will be the pressure?

Answer»

`2 N//m^2`
`2XX10^(-4)N//m^2`
`6 N//m^2`
`6xx10^(-4) N//m^2`

Solution :`P=("energy flux")/("SPEED")`
`=(18W //cm^2)/(3xx10^8 m//s)`
`=(18xx10^4 W//m^2)/(3xx10^8 m//s)`
`THEREFORE P=6xx10^(-4) N//m^2`


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