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The system of block and wedges all of same mass shown in the figure is released from rest. All surfaces are smooth. Then: |
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Answer» The speed of block `A` when it falls `50cm` is `2sqrt(2)m//s` Velocity direction of `A,B` and `C` `1/2mv^(2)+1/2m(V^(2)+(v^(2))/4)+1/2(MV^(2))/4=2mgh` `v=sqrt(8/5gh)=2sqrt(2)m//s` |
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