The system shown in figure is in equilibrium . The mass of the container with Liquid is M, density of liquid in the container is `rho` and the volume of the block is V. If the container is now displaced downwards through a distance `x_(0)` and released such that the block remains well inside the liquid then during subsequent motion A. time period of SHM of the container will be `2pisqrt((M)/(k))`B. time period of SHM of the container will be `2pisqrt((M+rhoV)/(k))`C. amplitude of SHM of the container is `x_(0)`D. amplitude of SHM of the container is `2x_(0)`

The system shown in figure is in equilibrium . The mass of the contain

1.	The system shown in figure is in equilibrium . The mass of the container with Liquid is M, density of liquid in the container is `rho` and the volume of the block is V. If the container is now displaced downwards through a distance `x_(0)` and released such that the block remains well inside the liquid then during subsequent motion A. time period of SHM of the container will be `2pisqrt((M)/(k))`B. time period of SHM of the container will be `2pisqrt((M+rhoV)/(k))`C. amplitude of SHM of the container is `x_(0)`D. amplitude of SHM of the container is `2x_(0)`
Answer» Correct Answer - B (b) `M_(e)`= Mass of container + `("Upthrust")/(g)` `M+(rhoVg)/(g)=M+rhoV`

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