1.

The system shown is released from rest. Mass of ball is m kg and that of wedge is M kg respectively. When ball reaches at highest point on other side of the wedge, velocity of ball and wedge is (initially wedge is kept at rest against a wall and there is no friction anywhere) :

Answer»

`(Msqrt(2 gR))/(m + M)`
`(Msqrt(2 gR))/(M)`
`M/m sqrt(2 gR)`
`(msqrt(2gR))/(m + M)`

Solution :Let h : HEIGHT gain by BALL above the bottom
`implies`Wedge will not move till the ball REACHES at bottom with velocity`sqrt(2gR)`
`implies m sqrt(2gR) = (m + M) V implies (msqrt(2 gR))/(m + M)`


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