1.

The table below shows the daily expenditure on food of 25 households in a locality. Daily expenditure (in Rs): 100 - 150 150 - 200 200 - 250 250 - 300 300 - 350 Number of households: 4 5 12 2 2Find the mean daily expenditure on food by a suitable method.

Answer»

We may calculate class marks (xi) for each interval by using the relation

xi \(=\frac{Upper\,class\,limit+lower\,class\,limits}{2}\)

Class size = 50

Now taking 225 as assumed mean we can calculate as follows:

 Daily expenditure (in Rs) fi di = xi - A = xi - 225ui = \(\frac{xi-225}{h}\)xifiui
 100 - 1504-100-2125-8
 150 - 2005-50-1175-5
 200 - 25012002250
 250 - 30025012752
 300 - 350210023254
 N = 25\(\sum\)fiui = -7

Mean (x̅) = A + \(\frac{\sum f_iu_i}{N}\times h\) 

\(=225+\frac{-7}{25}\times50\)

\(=225-14=211\)

So mean expenditure on food is 211


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