1.

The table records the mass and speed of an object travelling at constant velocity on a frictionless track, as performed by a student conducting a physics lab exercise. In her analysis, the student had to state the trial in which the object had the greatest momentum and the trial in which it had the greatest kinetic energy. which of the following gives the correct answer?

Answer»

Greatest Momentum-Trial 1, Greatest Kinetic Energy-Trial 3
Greatest Momentum-Trial 2, Greatest Kinetic Energy-Trial 2
Greatest Momentum-Trial 3, Greatest Kinetic Energy-Trial 2
Greatest Momentum-Trial 4, Greatest Kinetic Energy-Trial 4

Solution :Since momentum, p, is equal to mv, we just multiply the two entries (m and v) in each ROW of the table and see which one is the greatest. This occurs in triel 3, where p=(2KG)(2m/s)=4kg.m/s. so, the answer must be either (C) or (D). To decided which, we only need to find the kinetic energy of the OBJECT in trial 2 and trial 3 and choose the one that's greater. since `(1)/(2)mv^(2)=(1)/(2)(1KG)(3m//s)^(2)=(9)/(2)J` in trial 2, but only `(1)/(2)(2kg)(2m//s)^(2)=4J` is Trial 3, we seee that the object's kinetic energy is greater in trial 2, so the answer is (C).


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