1.

The temperature at which a black body radiates at the rate of 5.67"W cm"^(-2) is (sigma=5.67xx10^(-8)S.I.):

Answer»

100 K
500 K
1000 K
1500 K.

Solution :`E=5*67"W cm"^(-2)=5*67xx10^(4)"Wm"^(-2)`
Now `E=sigmaT^(4)""RARR""T=((E)/(sigma))^(1//4)`
`T=((5*67xx10^(4))/(5*67xx10^(-8)))^(1//4)=1000K`.
THUS correct choice is (c ).


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