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The temperature at which a black body radiates at the rate of 5.67"W cm"^(-2) is (sigma=5.67xx10^(-8)S.I.): |
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Answer» 100 K Now `E=sigmaT^(4)""RARR""T=((E)/(sigma))^(1//4)` `T=((5*67xx10^(4))/(5*67xx10^(-8)))^(1//4)=1000K`. THUS correct choice is (c ). |
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