The temperature at which rms velocities of nitrogen gas molecules will be doulbed that at `0^(@)C` isA. 273 KB. 546 KC. 136 KD. 1092 K

The temperature at which rms velocities of nitrogen gas molecules will

1.	The temperature at which rms velocities of nitrogen gas molecules will be doulbed that at `0^(@)C` isA. 273 KB. 546 KC. 136 KD. 1092 K
Answer» Correct Answer - D `C_(1)propsqrt(T_(1)) and C_(2) prop sqrt(T_(2))(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))` `therefore T_(2)=(C_(2)^(2))/(C_(1)^(2))T_(1)` `=4xx273=1092K`

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The temperature at which rms velocities of nitrogen gas molecules will be doulbed that at `0^(@)C` isA. 273 KB. 546 KC. 136 KD. 1092 K

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