1.

The temperature at which the mean KE of the molecules of gas is one - third of the mean KE of its molecules at `180^(@)C` isA. `-122^(@)C`B. `-90^(@)C`C. `60^(@)C`D. `-151^(@)C`

Answer» Correct Answer - D
Kinetic energy of a gas is directly proportional to its temperature.
`therefore " " (K_(1))/(K_(2))=(T_(1))/(T_(2))`
`rArr " " (K)/(K//3)=(273+180)/(T_(2))`
`rArr " " 3=(453)/(T_(2))`
`T_(2)=151^(@)C`


Discussion

No Comment Found

Related InterviewSolutions