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The temperature at which the mean KE of the molecules of gas is one - third of the mean KE of its molecules at `180^(@)C` isA. `-122^(@)C`B. `-90^(@)C`C. `60^(@)C`D. `-151^(@)C` |
Answer» Correct Answer - D Kinetic energy of a gas is directly proportional to its temperature. `therefore " " (K_(1))/(K_(2))=(T_(1))/(T_(2))` `rArr " " (K)/(K//3)=(273+180)/(T_(2))` `rArr " " 3=(453)/(T_(2))` `T_(2)=151^(@)C` |
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