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The temperature at which the root mean square velocity of the gas molecules would becomes twice of its value at `0^(@)C` isA. `819^(@)C`B. `1092^(@)C`C. `1100^(@)C`D. `1400^(@)C` |
Answer» Correct Answer - A `(C_t)/(C_0) = sqrt((273+t)/(273))` or `4 xx 273 - 273 = t` or `t = 3 xx 273 = 819^(@)C`. |
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