1.

The temperature at which the root mean square velocity of the gas molecules would becomes twice of its value at `0^(@)C` isA. `819^(@)C`B. `1092^(@)C`C. `1100^(@)C`D. `1400^(@)C`

Answer» Correct Answer - A
`(C_t)/(C_0) = sqrt((273+t)/(273))`
or `4 xx 273 - 273 = t`
or `t = 3 xx 273 = 819^(@)C`.


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