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The temperature coefficient of a material is 4 xx 10^(-4) per ""^(@)C. Calculate the temperature at which resistance of the conductor becomes 40% more than its value of 0^(@)C. |
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Answer» Solution :The RESISTANCE of the conductor at temperature `t ""^(@)C` is given by: `R= R_(0) (1 + alpha t)` `rArr 1.4 R_(0) = R_(0) (1 + 4 xx 10^(-4)t)` `rArr t= (0.4)/(4 xx 10^(-1)) = 1,000^(@)C` |
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