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The temperature drop through a two layer furnace wall is `900^@C`. Each layer is of equal area of cross section. Which of the following actions will result in lowering the temperature `theta` of the interface?A. By increasing the thermal conductivity of outer layer.B. By increasing the thermal conductivity of inner layer.C. By increasing thickness of outer layer.D. By increasing thickness of inner layer. |
Answer» Correct Answer - A::D Rate of heat flow `(K_(i)A(1000 - theta))/(l_(1)) = (K_(0)A (theta - 100))/(l_(0)) implies (theta-100)/(900) = (1)/(1 + (K_(0)l_(i))/(K_(i)l_(0)))` Now, we can see that `theta` can be decrease by increasing thermal conductivity of outer layer `(K_(0))` and thickness of inner layer ` (l_(1))`. |
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