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The temperature drop through a two layer furnace wall is `900^@C`. Each layer is of equal area of cross section. Which of the following actions will result in lowering the temperature `theta` of the interface?A. By increasing the thermal conductivity of outer layer .B. By increasing the thermal conductivity of outer layer .C. By increasing the thermal conductivity of outer layer .D. By increasing the thermal conductivity of outer layer . |
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Answer» Correct Answer - A::B H =rate of heat flow `=(900)/((l_(1))/((K_(i)A))+(l_(0))/(K_(0A)))` Now, `1000 -theta = (Hl_(i))/(K_(i)A)or` `theta=1000-[(900)/((l_(i))/(K_(i0A))+(l_(0))/(K_(0)A))](l_(i))/(K_(i)A)=100-(900)/(1+(l_(0)K)/(K_(0))(K_(i))/(l_(i)))` Now we can see that `theta` can be decreased by increasing thermal conductivity of outer layer `(K_(0))` and thickness of inner layer `(I_(i))` . |
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