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The temperature inside a refrigerator is `t_(2)^(@)C` . The amount of heat delivered to the room for each joule of electrical energy consumed ideally will beA. `(t_(2)+273)/(t_(1)-t_(2))`B. `(t_(1)+t_(2))/(t_(1)-273)`C. `(t_1)/(t_(1)-t_(2))`D. `(t_(1)+273)/(t_(1)-t_(2))` |
Answer» Correct Answer - D Heat delivered = `Q_(1)` `COP_(beta)=(t_(2)+273)/(t_2-t_1)=(Q_2)/(W)=(Q_(1)-W)/(W) = (Q_1)/(W)-1` `(Q_1)/(W) = 1+(t_(2)+273)/(t_(1)-t_(2))= (t_(1)+273)/(t_(1)+t_(2))` |
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