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The temperature of a room heated by heater is `20^@C` when outside temperature is `-20^@C` and it is `10^@C` when the outside temperature is `-40^@C`. The temperature of the heater isA. `80^@C`B. `100^@C`C. `40^@C`D. `60^@C` |
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Answer» Correct Answer - D Under steady state condition heat released to the room`=`heat dissipated out of the room Let `theta` be the temperature of heater Then `theta-20=alpha[20-(-20)]` .(i) and `theta-10=alpha[10-(-40)]` .(ii) Solving Eqs. (i) and (ii) we get we get `theta=60^@C` |
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