1.

The temperature of a silver bar rised by `10.0^@`C when it absorbs `1.23kJ` of energy by heat. The mass of bar is 525g. Determine the specific heat of silver.

Answer» We find its specific heat from the definition, which is contained in the equation `Q=mc_(silver)DeltaT` For energy input by heat to produce a temperature change. Solving we have
`c_(silver)=(Q)/(mDeltaT)`
`c_(silver)=(1.23xx10^3J)/((0.525kg)(10.0C))=234J//kg.^@C`


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