1.

The temperature of an ideal gas is increased from 140K to 560K. If at 140K, the root mean square velocity of the gas is x, at 560K it becomes

Answer»

5x
4x
2x
`x//2`

Solution :r.m.s. SPEED at 10 K = x
`:. x = sqrt(( 3R XX 560 )/( M ))`
at 560K,x. = `sqrt(( 3R xx 560)/( M))`
`( x.)/( x) = sqrt(( 560)/( 140)) = 2`
`x. = 2x`


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