The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K, the root mean square velocity of the gas molecules is v, then at 480 K, it will be

The temperature of an ideal gas is increased from 120 K to 480 K. If a

1.	The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K, the root mean square velocity of the gas molecules is v, then at 480 K, it will be
Answer» 4v 2v `v//2` `v//4` SOLUTION :Since M REMAINS the same, so `v_(rms)propsqrt(T)` `therefore (v_(1))/(v_(2))=SQRT((T_(1))/(T_(2)))=sqrt((120)/(480))=sqrt((1)/(4))=(1)/(2)` `v_(2)=2""[because v_(1)=v]`

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The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K, the root mean square velocity of the gas molecules is v, then at 480 K, it will be

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