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InterviewSolution
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The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is v, at 480 K it becomesA. 4 vB. 2 VC. `(v)/(2)`D. `(v)/(4)` |
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Answer» Correct Answer - B The root mean square volocity is given by `v"rms"=sqrt((3RT)/(M))` `So " "(v_(1))/(v_(2))=sqrt((T_(1))/(T_(2)))` Now , `T_(1)=120K,T_(2)=480K,v_(1)=v` `so, " " (v_(1))/(v_(2))=sqrt((120)/(480))=sqrt((1)/(4))=(1)/(2)` `rArr" " (v)/(v_(2))=(1)/(2)` `rArr" "v_(2)=2v` |
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