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The temperature of an iron piece is heated from `30^@ C "to" 90^@ C`. What is the change in its temperature on the fahrenheit scale and on the kelvin scale? |
Answer» `Delta C=90^(@)-30^(@) = 60^(@)C` Temperature difference on Fahrenheit Scale `DeltaF =(9)/(5)DeltaC =(9)/(5)(60^(@)C)=108^(@)F` Temperature difference on Kelvin Scale ` DeltaK= DeltaC = 60K` |
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