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The temperature of sink of Carnot engine is `27^(@)C`. Efficiency of engine is `25%`. Then temeperature of source isA. `27^(@)C`B. `127^(@)C`C. `327^(@)C`D. `227^(@)C` |
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Answer» Correct Answer - B `eta=1-(T_(2))/(T_(1))=(1)/(4)=1-(300)/(T_(1)),(300)/(T_(1))=(3)/(4):` `T_(1)=400K` `t_(1)=400-273` `=127^(@)C`. |
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