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The ten’s digit of a 2-digit number is 2 times its ones digit. If the digits are reversed, The sum of the original number & the number so formed is 66. Find the number. |
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Answer» ♤Let the number be “XY”, which values (10x+y).Given, x = 2y.When it is reversed, it BECOMES “YX”, which values (10Y+x).Also, (10x + y) + (10y + x) = 6611(x + y) = 66(x + y) = 6(2y + y) = 6Y = 2x = 4Original number = 42. |
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