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the tense and once digit of a two digit number are the same when the number added to its reverse the sum 88 what is the number |
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Answer» Let the DIGIT at TENS place be x and the digit unis place be y.Then the original number will be 10x+y.The digit at tens place is three times the digit at the units place.i.e. x=3y ....(1)The sum of this number and the number formed by reversing its digits is 88.(10x+y)+(10y+x)=88⇒11x+11y=88⇒x+y=8 ....(2)SUBSTITUTE the value of EQUATION (1) in equation (2).Therefore, 3y+y=8⇒4y=8⇒y=2Therefore, x=3y=3×2=6Therefore, the original number is 62. |
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