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The term mole first used by Ostwald in `1896` refers for the ratio of mass of a substance in `g` and its molecular weight. `1 "mole"` of a gaseous compound occupies `22.4 "litre"` at `NTP` and contains `6.023xx10^(23)` molecules of gas. The amount of sulphur required to produce `100 "mole"` of `H_(2)SO_(4)` is:A. `3.2xx10^(3)g`B. `32.65 g`C. `32 g`D. `3.2 g` |
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Answer» Correct Answer - A `1 "mole" H_(2)SO_(4)equiv 1 "mole" S equiv 32 g S` |
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