1.

The thermo emf of a hypothetical thermocouple varies with the temperature 0 of hot junction as E = atheta + btheta^2 in volts, where the ratio a/bis 700^@c. If the cold junction is kept at 0^@c, then the neutral temperature is

Answer»

`700^@c`
`1400^@c`
`390^@c`
No neutral TEMPERATURE is possible for this thermocouple

Solution :`E=atheta + bthera^(2)`
`P=(dE)/(dtheta) =(d(atheta + btheta^(2)))/(dtheta) =a+2btheta`
At, Neutral temperature, `theta=t_(n)`, P becomes zero
`a+2bt_(n)=0`
`THEREFORE t_(n)=- a/(2b) = - a/b . 1/2`
`=-700. 1/2 `[Given, `a/b=700^@C]`
`-350^@C`
Option not available


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