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The threshold frequency of a certain metal is v_(0). When frequency of incident radiation is 2v_(0), the maximum velocity of photoelectrons is found to be 3 xx 10^(6) m//s. If the frequency of radiataions is increased to 10v_(0), the maximum velocity of photoelectrons will be |
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Answer» `(3)/(10)xx10^(6) m//s` `KE_(2)=h(10v_(0))-hv_(0)=9hv_(0)` `(KE_(2))/(KE_(1))=9rArr(v_(2))/(v_(1))=3` |
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