1.

The threshold frequency of a certain metal is v_(0). When frequency of incident radiation is 2v_(0), the maximum velocity of photoelectrons is found to be 3 xx 10^(6) m//s. If the frequency of radiataions is increased to 10v_(0), the maximum velocity of photoelectrons will be

Answer»

`(3)/(10)xx10^(6) m//s`
`(10)/(3)xx10^(6) m//s`
`9 xx 10^(6) m..s`
`sqrt(3) xx 10^(6) m//s`

SOLUTION :`KE_(1)=h(2v_(0))-hv_(0)=hv_(0)`
`KE_(2)=h(10v_(0))-hv_(0)=9hv_(0)`
`(KE_(2))/(KE_(1))=9rArr(v_(2))/(v_(1))=3`


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