1.

The threshold frequency of a metal surface is 6.2 eV energy. Stopping potential for incident radiation is 5V. Then incident radiation lies in :

Answer»

X-RAYS region
Ultraviolet region
Infrared region
Visible region.

Solution :Here energy of photon `= omega_(0)+K.E`
`=6*2eV+5eV=11*2eV` which energy corresponds to that of ultraviolet rays.


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