1.

The threshold wavelength for a metal surface whose photoelectric work function is 3.313 eV is……………………

Answer»

4125 Å
3750 Å
6000 Å
2062.5 Å

Solution :`phi = hv_0 RARR phi = (HC)/(lambda_0)`
`:.lambda_0 = (hc)/(phi) = (6.6 xx 10^(-34)xx 3 xx 10^8)/(3.313 xx 1.6 xx 10^(-19))=3.7352 xx 10^(-7)`
`= 3.740 xx 10^(-7) rArr lambda_0 ~~ 3740 Å`


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